## Calculus with Applications (10th Edition)

$[3,+\infty)$
The domain is the set of all possible values of x for which a value f(x) exists. $(x-3)^{1/2}=\sqrt{x-3}$ produces a real number, that is, f(x) is defined only when the radicand $x-3$ is non-negative. So $x-3 \geq 0$ $x \geq 3,$ In interval notation, the domain is $[3,+\infty)$