# Chapter 2 - Nonlinear Functions - 2.1 Properties of Functions - 2.1 Exercises - Page 54: 11

Domain: $(-2,-1,0,1,2,3)$ Equation: $2y-x=5$ $2y=5+x$ $y=\frac{1}{2}x+\frac{5}{2}$ Ordered pairs: $(-2,1.5)(-1,2)(0,2.5)(1,3)(2,3.5)(3,4)$ Range: $(1.5,2,2.5,3,3.5,4)$

#### Work Step by Step

Step 1: The domain means all the $x$ values of the function Step 2: The original equation is $2y-x=5$ (make $y$ the subject) Step 3: Subtract $x$ from both sides of the equation Step 4: Divide with $2$ on both sides of the equation Step 5: In order to get the ordered pair, substitute $x$ with each of the values in the domain to get the $y$ values. Step 6: The range means all the $y$ values of the function

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