Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 13 - The Trigonometric Functions - Chapter Review - Review Exercises - Page 703: 99

Answer

$\cos(\theta)=\frac{1}{256}$ $\theta=\arccos\left(\frac{1}{256}\right) \approx 90^{\circ}$

Work Step by Step

From the previous part it follows: $$\cos(\theta)=\frac{r_2^{4}}{r_1^{4}}$$ $$\cos(\theta)=\frac{(\frac{1}{4})^{4}}{1^{4}}$$ $$\cos(\theta)=\frac{1}{256}$$ $$\theta=\arccos\left(\frac{1}{256}\right) \approx 90^{\circ}$$
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