Answer
$${\text{sin6}}{{\text{0}}^ \circ } = \frac{{\sqrt 3 }}{2}$$
Work Step by Step
$$\eqalign{
& {\text{sin6}}{{\text{0}}^ \circ } \cr
& {\text{using the }}{30^ \circ }{\text{ - 6}}{{\text{0}}^ \circ }{\text{ - 9}}{{\text{0}}^ \circ }{\text{ triangle to obtain}} \cr
& \sin {60^ \circ } = \frac{{{\text{opposite side to the 6}}{{\text{0}}^ \circ }}}{{{\text{hyppotenuse}}}} \cr
& {\text{then}} \cr
& {\text{sin6}}{{\text{0}}^ \circ } = \frac{{\sqrt 3 }}{2} \cr} $$
