Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 13 - The Trigonometric Functions - Chapter Review - Review Exercises - Page 701: 24

Answer

$${54^ \circ }$$

Work Step by Step

$$\eqalign{ & \frac{{3\pi }}{{10}} \cr & {\text{we know that 1 radian}} = \left( {\frac{{{{180}^ \circ }}}{\pi }} \right){\text{. }}\left( {{\text{see}}\,\,{\text{page 668}}} \right){\text{ Then}}{\text{,}} \cr & \frac{{3\pi }}{{10}}{\text{radians}} = \frac{{3\pi }}{{10}}\left( {\frac{{{{180}^ \circ }}}{\pi }} \right) \cr & {\text{multiplying}} \cr & \frac{{3\pi }}{{10}}{\text{radians}} = \frac{{3\left( {{{180}^ \circ }} \right)}}{{10}} \cr & \frac{{3\pi }}{{10}}{\text{radians}} = 3\left( {{{18}^ \circ }} \right) \cr & \frac{{3\pi }}{{10}}{\text{radians}} = {54^ \circ } \cr} $$
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