Chapter 11 - Probability and Calculus - 11.1 Continuous Probability Models - 11.1 Exercises - Page 575: 20

$=\frac{1}{6}x^{2}-\frac{1}{6}x-1$

Work Step by Step

We are given $f(x)=\frac{1}{3}x-\frac{1}{6}$ for $3\leq x \leq 4$ The cumulative distribution function is given by $F(x)=P(X\leq x)=\int^{x}_{3}(\frac{1}{3}t-\frac{1}{6})dt$ $=\frac{1}{6}t^{2}-\frac{1}{6}t|^{x}_{3}$ $=\frac{1}{6}x^{2}-\frac{1}{6}x-1$

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