Answer
$$y = \frac{1}{3}\ln \left| {3x + 2} \right| + C$$
Work Step by Step
$$\eqalign{
& \frac{{dy}}{{dx}} = \frac{1}{{3x + 2}} \cr
& {\text{Separating variables leads to}} \cr
& dy = \frac{1}{{3x + 2}}dx \cr
& {\text{To solve this equation}}{\text{, determine the antiderivative of each side}} \cr
& \int {dy} = \int {\frac{1}{{3x + 2}}dx} \cr
& y = \int {\frac{1}{{3x + 2}}} dx \cr
& {\text{integrating}} \cr
& y = \frac{1}{3}\ln \left| {3x + 2} \right| + C \cr} $$
