## Calculus: Early Transcendentals 8th Edition

$8\pi$
First, plug in 0 for y in $y = \sqrt x-1$ Second, solve for $x$ to get the intersection points which would tell your $a$ and $b$ Third, use the disk method $v=A(x)dx$ $A(x)$ being $A(x)=\int\pi*r^{2}$ Fourth, plug in the radius $\sqrt x-1$ and find the integral then solve.