Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.1 - Areas and Distances - 5.1 Exercises - Page 377: 23

Answer

$A = \lim\limits_{n \to \infty} \sum_{i=1}^{n}\sqrt{sin(\frac{\pi~i}{n}})\cdot \frac{\pi}{n}$

Work Step by Step

For each $x_i$, such that $1 \leq i \leq n$, note that $x_i = \frac{\pi~i}{n}$ $\Delta x = \frac{\pi}{n}$ We can express the area under the curve as a limit: $A = \lim\limits_{n \to \infty} [f(x_1)\Delta x+f(x_2)\Delta x+...+f(x_n)\Delta x]$ $A = \lim\limits_{n \to \infty} [f(\frac{\pi}{n})(\frac{\pi}{n})+f(\frac{2\pi}{n})(\frac{\pi}{n})+...+f(\frac{n\pi}{n})(\frac{\pi}{n})]$ $A = \lim\limits_{n \to \infty} [\sqrt{sin(\frac{\pi}{n}})(\frac{\pi}{n}) + \sqrt{sin(\frac{2\pi}{n}})(\frac{\pi}{n}) +...+\sqrt{sin(\frac{n\pi}{n}})(\frac{\pi}{n}) ]$ $A = \lim\limits_{n \to \infty} \sum_{i=1}^{n}\sqrt{sin(\frac{\pi~i}{n}})\cdot \frac{\pi}{n}$
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