Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.1 - Areas and Distances - 5.1 Exercises - Page 377: 18

Answer

$\approx7.22 \thinspace km$

Work Step by Step

On a velocity-time graph, the distance traveled can be found using the area under the curve. If we count the boxes under the curve between $t=0$ and $t=30s$, we see there are about 26 whole boxes. The size (area) of each box is: $20\ km/h\times5\ seconds = 100 \frac{km\thinspace s}{hr}$. There are 3600 seconds in an hour. $\left(\approx 26\ boxes*100\frac{km\thinspace s}{hr}\right)\left(\frac{hr}{3600\thinspace s}\right)\approx0.722\thinspace km$
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