Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Review - Exercises: 19

Answer

Does not exist since the function has an infinite discontinuity at $t = 4$. $f$ is discontinuous on the interval $[ 1,5]$.

Work Step by Step

$\int^{5}_1 \frac{dt}{(t-4)^{2}}$ $t -4 \ne 0$ $t \ne 4$ Does not exist since the function has an infinite discontinuity at $t = 4$. $f$ is discontinuous on the interval $[ 1,5]$.
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