## Calculus: Early Transcendentals 8th Edition

Does not exist since the function has an infinite discontinuity at $t = 4$. $f$ is discontinuous on the interval $[ 1,5]$.
$\int^{5}_1 \frac{dt}{(t-4)^{2}}$ $t -4 \ne 0$ $t \ne 4$ Does not exist since the function has an infinite discontinuity at $t = 4$. $f$ is discontinuous on the interval $[ 1,5]$.