Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Review - Exercises - Page 422: 10

Answer

$g''(4) = -2$

Work Step by Step

$g(x) = \int_{0}^{x}f(t)~dt$ Then we can say that $g'=f$ and $g'' = f'$ We can find $g''(4)$ which is $f'(4)$. This value is the slope of the graph of $f$ at the point $t = 4$: $g''(4) = f'(4) = \frac{-2-2}{5-3} = \frac{-4}{2} = -2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.