Answer
$f(1) = 8$
Work Step by Step
We know that:
$f'(x)=3-4x$
Thus:
$f(x) = 3x - 2x^2 + C$
Use the information given of $(2,5)$:
$5 = 3(2) - 2(2)^2 + C$
$5 = 6 - 8 + C$
$5 = -2 + C$
$7 = C$
$f(x) = 3x - 2x^2 + 7$
Substitute $x = 1$
$f(1) = 3(1) - 2(1)^2 + 7$
$f(1) = 3 - 2 + 7$
$f(1) = 8$
