Answer
$f(x) = x^{5} - x^{4} + x^{3}+Cx+D$
Work Step by Step
$f''(x) = 20x^{3} -12x^{2} +6x$
$f'(x) = 20(\frac{x^{4}}{4}) - 12(\frac{x^{3}}{3}) + 6(\frac{x^{2}}{2})$
$f'(x) = (\frac{20}{4})x^{4} - (\frac{12}{3})x^{3} + (\frac{6}{2})x^{2}$
$f'(x) = 5x^{4} - 4x^{3} + 3x^{2} + C$
$f'(x) = 5x^{4} - 4x^{3} + 3x^{2} + C$
$f(x) = 5(\frac{x^{5}}{5}) - 4(\frac{x^{4}}{4}) + 3(\frac{x^{3}}{3})+Cx$
$f(x) = x^{5} - x^{4} + x^{3}+Cx+D$
