Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.3 - How Derivatives Affect the Shape of a Graph - 4.3 Exercises - Page 303: 81

Answer

A: $\frac{d^{2}}{dx^{2}}(f*g)=((+)(+))+((+)(+))+((+)(+))+((+)(+))=4(+)$, concave up B: $\frac{d^{2}}{dx^{2}}(f*g)=((+)(+))+((-)(-))+((+)(+))+((-)(-))=4(+)$, concave up C: 1:$\frac{d^{2}}{dx^{2}}(f*g)=((-)(+))+((-)(+))+((+)(-))+((+)(-))=4(-)$, concave down 2: $\frac{d^{2}}{dx^{2}}(f*g)=((+)(+))+((+)(+))+((+)(-))+((+)(-))=2(+)+2(-)$, concavity depends on first derivatives 3: $\frac{d^{2}}{dx^{2}}(f*g)=((+)(-))+((+)(+))+((+)(-))+((+)(-))= (+)+3(-)$ AND the power of $f*g$ is one, linear, no concavity

Work Step by Step

We first rewrite functions in terms of sums using the product rule for both the first and second derivative. $\frac{d}{dx}(f*g)=(f*\frac{d}{dx}g)+(\frac{d}{dx}f*g)$ $\frac{d^{2}}{dx^{2}}(f*g)=\frac{d}{dx}((f*\frac{d}{dx}g)+(\frac{d}{dx}f*g))=(f*\frac{d^{2}}{dx^{2}}g)+(\frac{d^{2}}{dx^{2}}f*g)+(\frac{d}{dx}f*\frac{d}{dx}g)+(\frac{d}{dx}f*\frac{d}{dx}g)$ A: If a function is increasing, positive, and concave up, then the function and its first and second derivative must all be positive. Using the formula we used before, $\frac{d^{2}}{dx^{2}}(f*g)=((+)(+))+((+)(+))+((+)(+))+((+)(+))=4(+)$ and thus will be concave up. B: If a function is decreasing, positive, and concave up, then the first derivative must be negative, and the main function and second derivative must be positive $\frac{d^{2}}{dx^{2}}(f*g)=((+)(+))+((-)(-))+((+)(+))+((-)(-))=4(+)$ and thus will be concave up. C: 1: $f$ is negative concave down and $g$ is positive concave up, $f$ is increasing and $g$ is decreasing, so $\frac{d}{dx}f$ is postitive and $\frac{d}{dx}$ g is negative. $\frac{d^{2}}{dx^{2}}(f*g)=((-)(+))+((-)(+))+((+)(-))+((+)(-))=4(-)$, and thus will be concave down, depending on the size of the first derivatives. 2: $f$ is positive concave up and $g$ is positive convave up, $f$ is increasing and $g$ is decreasing, so $\frac{d}{dx}f$ is postitive and $\frac{d}{dx}$ g is negative. $\frac{d^{2}}{dx^{2}}(f*g)=((+)(+))+((+)(+))+((+)(-))+((+)(-))=2(+)+2(-)$, which means that the function can either be concave up or concave down. 3: $f$ is positive concave up, and $g$ is positive concave down, AND the power of $f*g=1$ $f$ is increasing and $g$ is decreasing, so $\frac{d}{dx}f$ is postitive and $\frac{d}{dx}g$ is negative. $\frac{d^{2}}{dx^{2}}(f*g)=((+)(-))+((+)(+))+((+)(-))+((+)(-))= (+)+3(-)$, but since the power of the product of $f*g$ is one, it makes the function linear, and thus, have no concavity. The arguments for A and B do not work for the scenarios in C because the first derivatives in these cases have different signs than in A and B, where they have the same sign.
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