Answer
We can see a sketch of one possible graph below.
Work Step by Step
$f'(x) \gt 0$ for all $x \neq 1$
The graph is increasing on the intervals $(-\infty, 1)\cup (1, \infty)$
There is a vertical asymptote at $x = 1$
$f''(x) \gt 0$ if $x \lt 1$ or $x \gt 3$
The graph is concave up on these intervals.
$f''(x) \lt 0$ if $1 \lt x \lt 3$
The graph is concave down on this interval.
