Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Review - Exercises - Page 361: 68

Answer

We can express the most general antiderivative $F(x)$ of the function as follows: $F(x) = -\frac{1}{2}x^{-2}+ sinh~x+C_1~~~~$ if $x \gt 0$ $F(x) = -\frac{1}{2}x^{-2}+ sinh~x+C_2~~~~$ if $x \lt 0$

Work Step by Step

We can find the most general antiderivative $F(x)$ of the function: $\int~f(x)$ $= \int (x^{-3}+ cosh~x)$ $= \int x^{-3}+ \int cosh~x$ $= \int x^{-3}+ \int \frac{e^x+e^{-x}}{2}$ $= \int x^{-3}+ \int \frac{e^x}{2}+ \int \frac{e^{-x}}{2}$ $= -\frac{1}{2}x^{-2}+ \frac{e^x}{2}- \frac{e^{-x}}{2}+C$ $= -\frac{1}{2}x^{-2}+ sinh~x+C$ Note that $-\frac{1}{2}x^{-2}$ does not exist when $x=0$ We can express the most general antiderivative $F(x)$ of the function as follows: $F(x) = -\frac{1}{2}x^{-2}+ sinh~x+C_1~~~~$ if $x \gt 0$ $F(x) = -\frac{1}{2}x^{-2}+ sinh~x+C_2~~~~$ if $x \lt 0$
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