Answer
$\frac{8}{3}x^{\frac{3}{2}}-2x^{3}+3x+C$
Work Step by Step
$\int (4\sqrt x-6x^{2}+3)dx$$= 4\int x^{1/2}dx-6\int x^{2}dx+3\int dx$
$=4\times\frac{2}{3}x^{3/2}-6\times\frac{x^{3}}{3}+3\times x+C$
$=\frac{8}{3}x^{\frac{3}{2}}-2x^{3}+3x+C$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 4 - Review - Exercises - Page 361: 65
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