Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Section 3.8 - Exponential Growth and Decay - 3.8 Exercises - Page 243: 13

Answer

It is quite possible to use potassium-40 to date a dinosaur fossil to 68 million years old since this age is much less than the half-life of potassium-40. The maximum age of a fossil that could be dated using potassium-40 is 12.46 billion years which is much older than the earth and almost as old as the universe.

Work Step by Step

We can find the value of $k$ when we use potassium dating: $m(t) = m(0)e^{kt}$ $m(1.25) = m(0)e^{1.25k} = 0.5~m(0)$ $e^{1.25k} = 0.5$ $1.25~k = ln(0.5)$ $k = \frac{ln(0.5)}{1.25}$ $k = -0.554518$ Then: $m(t) = m(0)~e^{-0.554518~t}$ We can find the time $t$ when only 0.1% remains: $m(t) = m(0)~e^{-0.554518~t} = 0.001~m(0)$ $e^{-0.554518~t} = 0.001$ $(-0.554518)~t = ln(0.001)$ $t = \frac{ln(0.001)}{-0.554518}$ $t = 12.46~$ billion years It is quite possible to use potassium-40 to date a dinosaur fossil to 68 million years old since this age is much less than the half-life of potassium-40. The maximum age of a fossil that could be dated using potassium-40 is 12.46 billion years which is much older than the earth and almost as old as the universe.
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