Calculus: Early Transcendentals 8th Edition

$dV = 1.96 m^3$
$v = \frac{2}{3} \pi r^3$ $\frac{dv}{dr} = 2\pi r^2$ Solve for $dv$: $dv = 2\pi r^2 dr$ $dv = 2\pi (25)^2 (0.0005)$ $dv = 1.96 m^3$