## Calculus: Early Transcendentals 8th Edition

$6t^2-6t-4$
First, look at each term separately using sum/difference rule. $\frac{d}{dx}(2t^3)-\frac{d}{dx}(3t^2)+\frac{d}{dx}(4t)$ Then take the derivative using the general power and constant multiple rules. $2*3t^2-3*2t+4*1$