## Calculus: Early Transcendentals 8th Edition

$$y'=e^{x+1}$$
$$y=e^{x+1}+1$$ $$y=e^x\times e+1$$ So, the derivative of $y$ is $$y'=e\frac{d}{dx}(e^x)+\frac{d}{dx}(1)$$ (since $e$ is a number) $$y'=e\times(e^x)+0$$ $$y'=e^{x+1}$$