Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.2 - The Limit of a Function - 2.2 Exercises: 32

Answer

$-\infty$

Work Step by Step

$\lim\limits_{x \to 5^-}\frac{x+1}{x-5}=\frac{6^-}{0^-}=-\infty$
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