#### Answer

$-\infty$

#### Work Step by Step

$\lim\limits_{x \to 5^-}\frac{x+1}{x-5}=\frac{6^-}{0^-}=-\infty$

Published by
Cengage Learning

ISBN 10:
1285741552

ISBN 13:
978-1-28574-155-0

$-\infty$

$\lim\limits_{x \to 5^-}\frac{x+1}{x-5}=\frac{6^-}{0^-}=-\infty$

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