## Calculus: Early Transcendentals 8th Edition

$$\frac{x^2-9}{x-3}=x+3$$ The right side of the equation $x+3$ is satisfied for $\forall x\in R$, so it is also satisfied for $x=3$. The left side of the equation $\frac{x^2-9}{x-3}$, however, is not satisfied for $x=3$. Since the left side and right side of the equation are not satisfied for the same set of numbers, they are false. In other words, the statement is false.