## Calculus: Early Transcendentals 8th Edition

$\lim\limits_{x \to 2} 4x^{2} - 11 =$ $\lim\limits_{x \to 2} 4(2)^{2} - 11 = 16 - 11 = 5$ So it's true that the function is continuous at $5$; $f(5) = 2$.