Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Review - True-False Quiz - Page 166: 17

Answer

True.

Work Step by Step

$\lim\limits_{x \to 2} 4x^{2} - 11 = $ $\lim\limits_{x \to 2} 4(2)^{2} - 11 = 16 - 11 = 5$ So it's true that the function is continuous at $5$; $f(5) = 2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.