## Calculus: Early Transcendentals 8th Edition

LHS = $\lim\limits_{x \to 2} (14 - 5x)$ $= 14 - 5(2)$ $= 4$ RHS = $4$ Therefore LHS = RHS
Substitute $x = 2$ into $14 - 5x$. Since the result is defined, solve the equation.