Answer
$176$
Work Step by Step
$Volume =\int_{0}^{2} \int_{1}^{4} x^2+4y^2 dy \space dx \\=\int_{0}^{2} [x^2y+\dfrac{4y^3}{3}]_1^4 dx \\=\int_0^2 3x^2 +84 dx \\=[x^3]_0^2 +84x |_0^2\\ =176$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 15 - Review - Exercises - Page 1063: 35
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