Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 15 - Review - Exercises - Page 1062: 4

Answer

$e-2$

Work Step by Step

$\int_{0}^{1}\int_{0}^{1}ye^{xy}dxdy=\int_{1}^{2}e^{xy})|_{0}^{1}dy$ $=\int_{0}^{1}e^{y}-1dy$ $=e^{y}-y|_{0}^{1}$ $=e-2$
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