Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 15 - Review - Exercises - Page 1062: 26



Work Step by Step

$\int\int_{D}ydA=\int_{1}^{2}\int_{1/y} ^{y} ydxdy$ $=\int_{1}^{2} [yx]|_{1/y} ^{y}dy$ $=\int_{1}^{2} y^{2}-1dy$ $=[\frac{y^{3}}{3}-y]_{1}^{2}$ $=[\frac{8}{3}-2]-[\frac{1}{3}-1]$ $=\frac{4}{3}$
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