Answer
$ \approx -0.27 L/s$
Work Step by Step
Write the chain rule for the given equation.
$\dfrac{dV}{dt}=\dfrac{\partial V}{\partial P}\dfrac{dP}{ dt}\dfrac{\partial V}{\partial T}\dfrac{dT}{dt}$
Plug in the given values.
, $\dfrac{dV}{dt}=(-8.31)\dfrac{T}{P^2})(\dfrac{dP}{ dt})+8.31(\dfrac{1}{P})(\dfrac{dT}{dt})$
This gives: $\dfrac{dV}{dt}=(-8.31)[-\dfrac{320}{(20)^2}) \times (0.05)+(\dfrac{1}{ 20})(0.15)]$
Hence, we have $ \dfrac{dV}{dt}\approx -0.27 L/s$
