Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.3 - Partial Derivatives - 14.3 Exercise - Page 926: 89

Answer

$T\dfrac{\partial P}{\partial T} \dfrac{\partial V}{\partial T}=mR$

Work Step by Step

Recall some relationships such as; $P= \dfrac{mRT}{V} ,V=\dfrac{mRT}{P}; T= \dfrac{PV}{mR}$ For $\dfrac{\partial P}{\partial T}$, here, all variables aside from $T$ to be treated as constants. and $\dfrac{\partial P}{\partial T}=\dfrac{\partial}{\partial T}[\dfrac{mRT}{V}]=\dfrac{mR}{V}$ $\dfrac{\partial V}{\partial T}=\dfrac{\partial}{\partial T}[\dfrac{mRT}{P}]=\dfrac{mR}{P}$ $T \times \dfrac{\partial P}{\partial T} \times \dfrac{\partial V}{\partial T}=(T) \dfrac{mR}{V} \times \dfrac{mR}{P}=\dfrac{PV}{mR} \times \dfrac{mR}{V} \times \dfrac{mR}{P}=mR$ Hence, we have $T\dfrac{\partial P}{\partial T} \dfrac{\partial V}{\partial T}=mR$
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