Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.3 - Partial Derivatives - 14.3 Exercise - Page 925: 71



Work Step by Step

$f(x,y,z)=xy^2z^3+\arcsin{(x\sqrt z)}$ In order to find $f_{xzy}$ we can differentiate in whatever order we want because of Clairaut's Theorem. $f_y=2xyz^3\Rightarrow f_{yx}=2yz^3\Rightarrow f_{yxz}=6yz^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.