Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Review - Exercises - Page 983: 32

Answer

$du=\dfrac{e^{2t}}{(1+se^{2t})}ds+\dfrac{2se^{2t}}{(1+se^{2t})}dt$

Work Step by Step

Given: $u=ln(1+se^{2t})$ $du=f_s(s,t)ds+f_t(s,t)dt$ Thus, $du=\dfrac{e^{2t}}{(1+se^{2t})}ds+\dfrac{2se^{2t}}{(1+se^{2t})}dt$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.