Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Review - Exercises - Page 983: 21

Answer

$f_{xx}=k(k-1)x^{k-2}y^lz^{m}$ $f_{xy}=klx^{k-1}y^{l-1}z^{m}$ $f_{yx}=klx^{k-1}y^{l-1}z^{m}$ $f_{yz}=lmx^{k}y^{l-1}z^{m-1}$ $f_{xz}=kmx^{k-1}y^{l}z^{m-1}$ $f_{zx}=kmx^{k-1}y^{l}z^{m-1}$ $f_{yy}=l(l-1)x^ky^{l-2}z^{m}$ $f_{yz}=lmx^ky^{l-1}z^{m-1}$ $f_{zy}=lmx^ky^{l-1}z^{m-1}$ $f_{zz}=m(m-1)x^ky^{l}z^{m-2}$

Work Step by Step

Given: $f(x,y,z)=x^ky^lz^m$ $f_{xx}=k(k-1)x^{k-2}y^lz^{m}$ $f_{xy}=klx^{k-1}y^{l-1}z^{m}$ $f_{yx}=klx^{k-1}y^{l-1}z^{m}$ $f_{yz}=lmx^{k}y^{l-1}z^{m-1}$ $f_{xz}=kmx^{k-1}y^{l}z^{m-1}$ $f_{zx}=kmx^{k-1}y^{l}z^{m-1}$ $f_{yy}=l(l-1)x^ky^{l-2}z^{m}$ $f_{yz}=lmx^ky^{l-1}z^{m-1}$ $f_{zy}=lmx^ky^{l-1}z^{m-1}$ $f_{zz}=m(m-1)x^ky^{l}z^{m-2}$
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