Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 13 - Section 13.1 - Vector Functions and Space Curves - 13.1 Exercises - Page 854: 8

Answer

Thus the curve is a parabola with vertex $( -1,0)$ that opens to the right.

Work Step by Step

The corresponding parametric equations for this curve are $x$ $=$ $t^2$ $-$ $1$, $y$ $=$ $t$. So, we can eliminate the parameter: $t$ $=$ $y$ becoming to $x$ $=$ $y^2$ $-$ $1$, $with$ $y$ $\in$ $R$, Thus the curve is a parabola with vertex $( -1,0)$ that opens to the right. By comparing the different values of $t$, we can find the direction in which $t$ increases as indicated in the graph.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.