Answer
the curve is a circle of radius $2$ centered at $(0,0,1)$ in the horizontal plane $z = 1$.
Work Step by Step
The corresponding parametric equations are
$x$ $=$ $2$ $cost$, $y$ $=$ $2$ $sint$, $z$ $=$$1$.
Eliminating the parameter in $x$ and $y$ gives
$x^2$ $+$ $y^2$ $=$ $4cos^2t$ $+$ $4sin^2t$ $=$ $4$$($$cos^2t$ $+$ $sin^2t$ $)$ $=$ $4$.
since $z$ $=$ $1$, the curve is a circle of radius $2$ centered at $(0,0,1)$ in the horizontal plane $z = 1$.
