Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.4 - The Cross Product - 12.4 Exercises - Page 822: 48

Answer

$a \times b=b \times c =c \times a$

Work Step by Step

$a+b+c=0$ then $b=-a-c$ $a \times b=a \times (-a-c)=-a \times c$ $a \times b=c \times a$ ... (1) $a+b+c=0$ then $a=-b-c$ $a \times b=(-b-c) \times b=-c \times b$ $a \times b=b \times c$ ...(2) From equations (1) and (2), we have $a \times b=b \times c =c \times a$ Hence, $a \times b=b \times c =c \times a$
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