Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 12 - Section 12.4 - The Cross Product - 12.4 Exercises - Page 822: 39

Answer

$10.6 N m$

Work Step by Step

$| \tau|=|r \times f|= |r||f|sin \theta$ Given: $r$=18 cm =0.18 m, $f=60 N,\theta=80 ^ \circ$ $| \tau|=|r \times f|= |r||f|sin \theta$ $=0.18 \cdot 60 \cdot sin (80 ^ \circ)$ $ \tau =10.6 Nm$
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