Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.8 - Power Series - 11.8 Exercises - Page 751: 31

Answer

$R=k^{k}$

Work Step by Step

Let $a_{n}=\frac{(n!)^{k}x^{n}}{(kn)!}$, then $\lim\limits_{n \to \infty}|\frac{a_{n+1}}{a_{n}}|=\lim\limits_{n \to \infty}|\dfrac{\frac{((n+1)!)^{k}x^{n+1}}{(k(n+1))!}}{\frac{(n!)^{k}x^{n}}{(kn)!}}|$ $=|x|(\frac{1}{k})^{k}$ $=|x|(\frac{1}{k})^{k}\lt 1$ Hence, $R=k^{k}$
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