Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.1 - Sequences - 11.1 Exercises - Page 704: 33


The sequence diverges.

Work Step by Step

Since the highest degree of $n$ in the numerator is 2 and the highest degree in the denominator is 3/2, the limit as $n$ approaches infinity will be that of $\frac{n^2}{n^{3/2}} = \sqrt{n}$. Hence the sequence diverges.
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