Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.1 - Sequences - 11.1 Exercises - Page 704: 30


$\lim\limits_{n \to \infty}$ $\frac{4^{n}}{(1+9^{n})}$ = 0

Work Step by Step

Divide top and bottom by $9^n$. We have $\lim\limits_{n \to \infty}$ $\frac{(\frac{4}{9})^{n}}{(\frac{1}{9^{n}})+1}$ = $\frac{0}{1}$ = 0.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.