## Calculus: Early Transcendentals 8th Edition

$\lim\limits_{n \to \infty}$ $\frac{4^{n}}{(1+9^{n})}$ = 0
Divide top and bottom by $9^n$. We have $\lim\limits_{n \to \infty}$ $\frac{(\frac{4}{9})^{n}}{(\frac{1}{9^{n}})+1}$ = $\frac{0}{1}$ = 0.