Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.3 - Polar Coordinates - 10.3 Exercises - Page 666: 4

Answer

(a) We can see the point $(4,\frac{4\pi}{3})$ on the graph. The Cartesian coordinates are $(-2,-2\sqrt{3})$ (b) We can see the point $(-2,\frac{3\pi}{4})$ on the graph. The Cartesian coordinates are $(\sqrt{2},-\sqrt{2})$ (c) We can see the point $(-3,-\frac{\pi}{3})$ on the graph. The Cartesian coordinates are $(-\frac{3}{2},\frac{3\sqrt{3}}{2})$

Work Step by Step

(a) We can see the point $(4,\frac{4\pi}{3})$ on the graph. We can find the Cartesian coordinates: $x = 4~cos~\frac{4\pi}{3} = -2$ $y = 4~sin~\frac{4\pi}{3} = -2\sqrt{3}$ The Cartesian coordinates are $(-2,-2\sqrt{3})$ (b) We can see the point $(-2,\frac{3\pi}{4})$ on the graph. We can find the Cartesian coordinates: $x = -2~cos~\frac{3\pi}{4} = \sqrt{2}$ $y = -2~sin~\frac{3\pi}{4} = -\sqrt{2}$ The Cartesian coordinates are $(\sqrt{2},-\sqrt{2})$ (c) We can see the point $(-3,-\frac{\pi}{3})$ on the graph. We can find the Cartesian coordinates: $x = -3~cos~\frac{-\pi}{3} = -\frac{3}{2}$ $y = -3~sin~\frac{-\pi}{3} = \frac{3\sqrt{3}}{2}$ The Cartesian coordinates are $(-\frac{3}{2},\frac{3\sqrt{3}}{2})$
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