Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Section 10.3 - Polar Coordinates - 10.3 Exercises - Page 666: 19

Answer

The cartesian form of the expression is $x^{2}-y^{2}=1$ which is a unit hyperbola opening in the x-direction.

Work Step by Step

We are told that $r^{2}cos2\theta=1$. Using the double angle identity for cosine, we get $r^{2}(cos^{2}\theta-sin^{2}\theta)=1$. Distributing, we get $r^{2}cos^{2}\theta-r^{2}sin^{2}\theta=1$. We can rewrite this as $(rcos\theta)^{2}-(rsin\theta)^{2}=1$. Using the polar-to-cartesian substitutions of $x=rcos\theta$ and $y=rsin\theta$, we can rewrite the entire expression as $x^{2}-y^{2}=1$, which is a unit hyperbola opening in the x-direction.
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