Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 67: 38


a) $e^{-\ln2}=\frac{1}{2}$ b) $e^{\ln(\ln e^3)}=3$

Work Step by Step

a) $e^{-\ln2}=e^{\ln2^{-1}}=e^{ln\frac{1}{2}}=\frac{1}{2}$ b) $e^{\ln(\ln e^3)}=\ln e^3=3\ln e=3$
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