Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 67: 27


$f^{-1}(x)=0.25x^{2}-0.75$ = blue line $f(x)=\sqrt {4x+3}$ =green line

Work Step by Step

Find the inverse: $f(x)=y=\sqrt {4x+3}$ $y^2=4x+3$ $x=0.25(y^2-3)$ $x=0.25y^2-0.75$ switch $x$ and $y$: $y=0.25x^2-0.75$ Yes, the inverse graph is a reflection over the line of y=x.
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