## Calculus: Early Transcendentals 8th Edition

$f^{-1}(x)=0.25x^{2}-0.75$ = blue line $f(x)=\sqrt {4x+3}$ =green line
Find the inverse: $f(x)=y=\sqrt {4x+3}$ $y^2=4x+3$ $x=0.25(y^2-3)$ $x=0.25y^2-0.75$ switch $x$ and $y$: $y=0.25x^2-0.75$ Yes, the inverse graph is a reflection over the line of y=x.