Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.4 - Exponential Functions - 1.4 Exercises - Page 53: 2

Answer

$a)16$ $b)27x^7$

Work Step by Step

$a) 8^{\frac{4}{3}}=(\sqrt[3] 8)^4=2^{4}=16$ $b)x(3x^{2})^3=3^3(x^2)^3x=27x^7$
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