Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises: 48

Answer

$g(t)=\tan t$ $f(t)=\frac{t}{1+t}$

Work Step by Step

Separating the function into two processes: $1. g(t)=\tan t$ $2. f(g(t))= f(\tan t)=\frac{\tan t}{1+\tan t}=\frac{g(t)}{1+g(t)}$ $f(t)=\frac{t}{1+t}$
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