Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.3 - New Functions from Old Functions - 1.3 Exercises - Page 44: 42

Answer

$f(g(h(x)))=tan(\frac{\sqrt[3] x}{\sqrt[3] x-1})$

Work Step by Step

We need to find $f(g(h(x)))$. To do this we can first substitute g(x) into our f(x) equation. $f(g(x))=tan(\frac{x}{x-1})$. Next, we can further substitute in h(x) into our previous function to create $f(g(h(x)))=tan(\frac{\sqrt[3] x}{\sqrt[3] x-1})$ .
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