#### Answer

a) $(-5, 3)$
b) $(-5, -3)$

#### Work Step by Step

a) Since the function is even, $f(x) = f(-x)$
$f(5) = f(-5)=3$
$\therefore (-5, 3)$ must also be on the graph.
b) Since the function is odd, $f(x) = -f(-x)$
$f(5) = -f(-5)=3$
$f(-5)=-3$
$\therefore (-5, -3)$ must also be on the graph.