#### Answer

Perimeter = $2A+\frac{32}{A}$, $A\gt0$

#### Work Step by Step

Let the lengths of the rectangle be $A$ and $B$, where $A\ne B$.
Area = $AB=16$
$B=\frac{16}{A}$
Perimeter = $2A+2B=2A+\frac{32}{A}$
$\because$ lengths are positive, $A\gt0$
$B=\frac{16}{A}\gt0$